In a promotion with an equal number of boys and girls, 1/8 of the girls and 5/6 of the boys are honorary students. What part of the class is made up of boys who are not honor students (1/8) + (5/6) = 23/24
total number of students = 24
12 boys 12 girls
5/6 honor students
1-5/6 = non-honored students
1/6 = non-honored students
(1/6)*12=2 non-honored students
2/24 = 1/12 Your answer is slightly out of step with the statement and incorrect, showing ambiguity.
The following solution might erase the meaning:
Total number of students = (1/8)+(5/6)= 46/48
Total girls = 24
Total Boys = 24
Honor boys= (5/6)*24= 20
Boys not honored = 24-20 = 4
so part of class unhonored boys are = 4*(1/48)= 1/12 1/2 of 1/6 is 1/12 let no of class=x,boys and girls are equal,boys=1 / 2x, 5/6*1/2x are honored, so 1-5/6=1/6 are not= x(1 – 5/12)=1/12x