From 130 feet away, a person on a bicycle heads towards a checkpoint and then passes it. The cyclist moves at a constant rate of 25 feet per second. The distance between the bike and the control point is given by the equation d=|130-25t|. What time is the bike 15 feet from the checkpoint. a. 4.6s and 9.2s
b. 2.9s and 5.8s
vs. 4.6s and 5.8s
D. 2.9 sec and 3.3 sec For this question you can say d = 15 feet so we need the t then you can say:
15 = l 130 – 25t l ⇒ because of the absolute value we should say:
1) 130 – 25t = 15 ⇒ -25t = 15 – 130 ⇒ – 25t = -115 ⇒ t = 115/25 = 4.6s
2) 130 – 25t = -15 ⇒ -25t = -15 – 130 ⇒ -25t = -145 ⇒ t = 145/25 = 5.8s
so the answer is c :))
I hope this is useful
good day your not helpful Damon just say the answer damon is not helpful=confirmed Thanks toof. so what is the answer? Does anyone have all the answers for the test????? I agree Damon you helped me d = 130 – 25 t
Where
d = -(130 -25 t) = -130 + 25 t Hey, I think you can solve these two equations!