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A mountain peak C is at 4130 feet. Above sea level, and from C, the angle of elevation of a second vertex B is 5.0°. An aviator in A directly above peak C finds angle CAB to be 43.8° when his altimeter reads it is 8460 feet above sea level. Find the height of peak B. Draw a diagram. You can see that if B and C are separated by a horizontal distance of x ft, then
x/(8460-h) = tan43.8°
(4130-h)/x = tan5°
eliminating x, we get
(8460-h)tan43.8° = (4130-h)/tan5°
h = 3734
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