A 4 kg block of wood lies on a table. the coefficient of friction between the block and the table is .40. a 5 kg mass is attached to the block by a horizontal rope passed over a frictionless pulley of negligible mass what is the acceleration of the block when the 5 kg mass is released? what is the tension of the rope when accelerating? Force applied = 5 kg x 9.8 = 49 N
Force against (friction)=4kgx9.8x.4=15.68
first to find the acceleration…
49-15.69=Total force= 33.32N
F=MA F/M=A 33.32/9(both boulders)= 3.702m/ss
Now for Voltage..
9.8-3.702=6.098
6.098X5=30.49N=Voltage